Google Interview Questions for Software Engineer
For an organization to be tagged with the ever-fancy word “successfully”, it must be installed with people who are passionate about their work and most importantly they should have interests that align with the vision of the organization. In this article, we will look into the different questions that are frequently noticed in Google Coding Interview Questions. This will provide a framework or blueprint for those who are preparing to appear in such an interview.
This is important in the sense that the workers are the one who sits on the driving seat, the organization just act as GPS who guides their employees in which direction, they need the vehicle to steer so as to reach the particular goal. This sets up the importance of having the right employee in the organization and this becomes more important when the organization that we are talking about is among the giants in the tech industry i.e. Google.
Google being a product-based company emphasizes a lot on their mechanism for selection of staff, they often prefer taking up fresh graduates straight from colleges as interns and then monitor their work and if they fulfill their requirement criteria, they offer the position in the company. There are various stages that a desirable candidate needs to go through before he gets his place booked in Google, there are few coding rounds, GDs at times, aptitude exams maybe and then, a technical interview is scheduled. Let's go through some of the Google data scientist interview.
Google Coding Interview Questions
#include
#include
int main()
{
char str[100];
int i, j, k;
printf("\n Please Enter any String : ");
gets(str);
for(i = 0; i < strlen(str); i++)
{
for(j = i + 1; str[j] != '\0'; j++)
{
if(str[j] == str[i])
{
for(k = j; str[k] != '\0'; k++)
{
str[k] = str[k + 1];
}
}
}
}
printf("\n The Final String after Removing All Duplicates = %s ", str);
return 0;
}
For explicit calculations Harshad number or Niven numbers for a given number base represents an integer which is divisible by the sum of its own digit for example 112, the sum of digits of 112 is 4 and 112 is itself divisible by 4 so it comes under the category of a Harshad Number. These numbers in the base are also known by the name n-Harshad numbers. Defining all numbers in the form of positive integer which is also divisible by the sum of its digits in bases n>2. The numbers which are all Harshad numbers are 1, 2, 4 and 6. In order to check if a number is a Harshad number or not we can follow-
- Input number
- Calculate the sum of its digits
- If the number is divisible by the sum of digits, print "Harshad number"
- If the number is not divisible by the sum of its digits, print "not Harshad number
There are many such kinds of numbers with different peculiar properties and one should know at least the popular ones.
Google Interview Questions and Answers have a keen love for Data Structure and its concepts. They intentionally put on efforts to frame questions for candidates which will check the understanding and application of the concepts related to Data Structure. Speed and compilation time are given utmost importance in such Google interview questions for Software Developers. The program designed by the candidate should be fast, efficient and effective. One more major concern is the space the program covers up in the RAM, the programs developed should be made in such a way that it takes up a small portion of RAM while run time.
Deadbeef represents a hexadecimal value that is utilized for debugging back the mainframe as it indicates the deadlock or any potential software crash in the embedded systems. While marking aur detecting the specific memory present in pages of hexdump it is easy with the help of Deadbeef.
It has three most advantages sides
- For old systems, it is used to fill the allocated memory to coax out any memory issue
- It may be sad as a pun for the term "dead meat"
- If any value winds up in pointer it is possible to induce the memory out of range issue.
Using the binary search option the location for any particular integer can be distinguished. The number can be compared in between array along with X and if the value is equal then the search is complete. If the number gets better then we have to search through the other half in the array. If the very much smaller. this process can be repeated until the search results get appropriate and half of the array is compared in between the center of the array along with x. This search can actively be narrowed by utilizing the factors and it is to be repeated until the value of x is found. The algorithm for the same consumes 0(log n) time.
Basically to add certain integer along with another number we would follow through-
MyInteger int1 = new MyInteger(5);
MyInteger int2 = new MyInteger(7);
MyFloat float1 = new MyFloat(3.14);
MyDouble doub1 = new MyDouble(2.71);
print(int1.add(int2));
print(int1.add(float1));
print(int1.add(doub1));
There are plenty of ways to prevent deadlock but the most reliable method is where we assign a particular order to the locks and then the same locks will be acquired by a different order. For example, consider that if certain threads need to acquire the locks of 1, 7 and 2 it is essential for it to acquire lock 1, which is then followed by lock 2 and lastly by lock 7. Following through this way we can easily prevent the thread trying to acquire the lock 1 followed by the lock 2 and different theatre trying to acquire the lock 2 and then lock 1. All of these together can contribute to deadlock. Though this is not the most frequent practice but still it is considered by many users.
A Jupyter notebook type interface is provided by Google in order to run python code upon the virtual machines. The collaboratory serves as a research tool to facilitate machine learning and It supports Python 2.7 and 3.6.
This can be done by following through the below-mentioned steps
- Open your collab. research page
- Select the option of new python3 notebook
- now you have to carefully type the code in code labs importing all the essential libraries
- In order to add new cells, click Insert->Code Cell
- To run a cell, select it and press Ctrl + Enter keys
By keeping a close track of 2 pointers in the associated linked list and then starting them to the beginning of the same list. With every iteration of the algorithm if the two pointers remain the same other than the beginning then there is a cycle in the algorithm. In case any of the pointer reaches the end of the linked list prior to the pointers remain the same then there is no cycle present in the algorithm. For pointers it is required to do not move one or two nodes at any particular time and it is only required that pointers frequently move at different rates. This process can hardly take 0(n) time.